m6032550g2
http://sathaporn.exteen.com/20070515/name6032550
may31,2550b.e.
coulomb_potential1
- http://media1.podbean.com/podcast-blog-audio-video-media-files/blogs/2231/uploads/m6032550g2potential1.xls
- http://members.thai.net/PHYSICSMATAYOM/coulomb/coulomb1.htm
worksheet1
http://www.editgrid.com/user/physicsmatayom/M6032550G2EXCEL1
worksheet2
worksheet3
JUN13,2550b.e.
| m 6032550G2Electric Field1 สนามไฟฟ้า | ||||
| E=KQ/r^2 | ||||
| input K(N.m^2/C^2)= | 9.00E+09 | |||
| input Q(C)= |
|
|||
| r(m) | 1/r,(m^-1) | 1/r^2,(m^-2) | E(N/C)=K*Q/r^2 | |
| 1 | 1.00 | 1.00 | 9.00E+09 | |
| 2 | 0.50 | 0.25 | 2.25E+09 | |
| 3 | 0.33 | 0.11 | 1.00E+09 | |
| 4 | 0.25 | 0.06 | 5.63E+08 | |
| 5 | 0.20 | 0.04 | 3.60E+08 | |
| 6 | 0.17 | 0.03 | 2.50E+08 | |
| 7 | 0.14 | 0.02 | 1.84E+08 | |
| 8 | 0.13 | 0.02 | 1.41E+08 | |
| 9 | 0.11 | 0.01 | 1.11E+08 | |
| 10 | 0.10 | 0.01 | 9.00E+07 | |
-
Graph
http://sathaporn.exteen.com/images/m6032550g2/m6032550g2electricfield11.GIF
http://sathaporn.exteen.com/images/m6032550g2/m6032550g2electricfield12.GIF
http://sathaporn.exteen.com/images/m6032550g2/m6032550g2electricfield13.GIF
worksheet4
worksheet5
worksheet6
worksheet7
http://media1.podbean.com/podcast-blog-audio-video-media-files/blogs/2231/uploads/M6032550G2LDR.xls
worksheet8EMF1
- GRAPH ;V=E-r*I
- SLOPE=-r=?
- INTERCEPT=E=?
worksheet9
- Florentz=qvxB;Vector_Force
- Florentz=qvBsin(theta)
- Fc=mv^2/R
- R=mv/qB
- (1/2)mv^2=qV
- q/m=?
worksheet10
F=LIxB and Vector_force
F=LIBsin(theta)
F12=L1I1xBI2
F21=L2I2xBI1
solenoid
D.C.motor & M=IBANcos(theta)
ELECTROMAGNETIC INDUCTION
- DC DYNAMO E=Df/Dt
- BACK EMF IN DC MOTOR
- TRANFORMER ;E2/E1=N2/N1
PHYSICS40205
worksheet2
http://www.piano-midi.de/midis/mozart/mz_331_3.mid
http://sathaporn.exteen.com
NUTTHAPORN_NARAT_THANAWAT
Producer
http://www.editgrid.com/user/physicsmatayom/M6032550G2rac1
-
PHYSIC RAC_1
- q=w*t
- w=2*p*f
- v=vm*sin(q+f)
- I=Im*sin(q+f)
- Pm=Im*vm
- P=Pm*sin2(q+f)
- Peffective=Paverage=Pm/2
- Irms=Iroot_mean_squer=Im/SQRT(2)
- vrms=vroot_mean_squer=vm/SQRT(2)
-
NOTE_Math
- Paverage=(1/2p)∫0p[Pm*sin2(q)]d(q)
- sin2q=[1/2-cos2q/2]
- ∫02psin2qdq=∫0p[1/2-cos2q/2]d(q)
- ∫02p[1/2]d(q)=[q/2]0p=[(2p)/2-(0/2)]=p
- ∫02pcos2qdq=(1/2)∫02pcos2qdq
- ∫02pcos2qdq=(1/2)[sin2q]02p=(1/2)[sin4p-sin0]=0
- Paverage=Pm*(1/2p)*[p-0]=1/2=Pm/2
- Q.E.D.
Paverage=Pm/2
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edit @ 13 Feb 2008 22:03:40 by physicsmatayom


